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24x^2-120x+144=0
a = 24; b = -120; c = +144;
Δ = b2-4ac
Δ = -1202-4·24·144
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-24}{2*24}=\frac{96}{48} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+24}{2*24}=\frac{144}{48} =3 $
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